2x^2=1.1x^2+24.9

Solution for 2x^2=1.1x^2+24.9 equation:

2x^2=1.1x^2+24.9

We move all terms to the left:

2x^2-(1.1x^2+24.9)=0

We get rid of parentheses

2x^2-1.1x^2-24.9=0

We add all the numbers together, and all the variables

0.9x^2-24.9=0

a = 0.9; b = 0; c = -24.9;
Δ = b2-4ac
Δ = 02-4·0.9·(-24.9)
Δ = 89.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{89.64}}{2*0.9}=\frac{0-\sqrt{89.64}}{1.8}
=-\frac{\sqrt{}}{1.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{89.64}}{2*0.9}=\frac{0+\sqrt{89.64}}{1.8}
=\frac{\sqrt{}}{1.8}
$